Tag: Compound Microscope

  • Len’s power and combinations

    Len’s power

    The degree to which a lens deviate light is called the optical power.

    Optical power measures how sharp the lens bends light that passes through it . Optical power P is given by P=1/f where f is the focal length of the lens. From the equation, one can see that the shorter the focal length, the higher the optical power. The unit for optical power is m-1 .

    m-1 is known as dioptre (D)

    Len’s Combination

    If an object is placed infront of a combination of two or more lenses, it’s image in the first lens becomes the object for the second lens which in turn produces another image. If there is a third lens, the second image becomes it’s object.

    One application of the Len’s combination is the compound microscope which combines two converging lenses of short focal length. In the microscope, the lens near the object is known as the objective lens and one near the eye is referred to as the eyepiece. Eyepiece has longer focal length compared to objective lens.

    Compound microscope structure

    The object to be viewed is placed between Fo and 2Fo of the objective lens so that a real inverted and magnified image is formed. This image is infront of the eyepiece and will act as an object to it. The eyepiece is adjusted so that this image falls between it’s principal focus Fo and itself so that a virtual but magnified image is obtained. The eyepiece therefore acts as a magnifying glass and produces a final image that is greatly magnified as in the figure above

    Compound Microscope magnification

    Magnification of objective lens mo = u/v where v is the distance of the first image from the objective lens and u the object distance. Taking fo as the focal length of the object lens, then from the lens formula:

    1/v + 1/u = 1/fo

    multiplying through by v;

    1 + v/u = v/fo

    substituting mo = u/v; we have

    1 + mo = v/fo and so mo = v/fo -1

    similarly, magnification me produced by the eyepiece will be given as:

    me = D/fe -1

    where D is the distance of first image from the lens.

    Total magnification produced by this lens arrangement is the product of mo and me

    That is, Total magnification = ( D/fe -1)(v/fo -1 )

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