Consider a right-angled triangle ABC below.

The angle θ can be expressed in terms of cosine ratio or sine ratio. The hypotenuse of the triangle has dimension r.
Adjacent side to angle θ is the line AB and the opposite side to the angle θ is line BC.
expressing angle θ in terms of cosine ratio and sin ratio:

by use of Pythagoras theorem:
(AB)2 + (BC)2 = r2
(rcosθ)2 + (rcosθ)2 = r2 and hence
r2 cos2 θ + r2 sin2 θ = r2
then dividing everywhere by r2 , then we get
cos2 θ + sin2 θ =1 which is a trigonometric identity which holds true for all values of θ.
Example
If tan θ = a, show that:

solution
we factor out cosθ to get:

but sin2 θ + cos2 θ =1
hence:

but tanθ = a, so 1/tanθ = 1/a
Related Topics
- Using tangents to solve triangles
- Table of tangents
- Equations of a circle
- Trigonometry
- Angle Tangents

